(y^2)+(4y)+(20)=0

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Solution for (y^2)+(4y)+(20)=0 equation:


Simplifying
(y2) + (4y) + (20) = 0
y2 + (4y) + (20) = 0
y2 + (4y) + 20 = 0

Reorder the terms:
20 + (4y) + y2 = 0

Solving
20 + (4y) + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-20' to each side of the equation.
20 + (4y) + -20 + y2 = 0 + -20

Reorder the terms:
20 + -20 + (4y) + y2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + (4y) + y2 = 0 + -20
(4y) + y2 = 0 + -20

Combine like terms: 0 + -20 = -20
(4y) + y2 = -20

The y term is (4y).  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
(4y) + 4 + y2 = -20 + 4

Reorder the terms:
4 + (4y) + y2 = -20 + 4

Combine like terms: -20 + 4 = -16
4 + (4y) + y2 = -16

Factor a perfect square on the left side:
(y + 2)(y + 2) = -16

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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